How position changes in accelerated motion

The last step in building a model for motion is to develop a single equation that relates position, velocity, time, and acceleration. Because velocity may not be constant, we use the fact that distance is equal to area on the v vs. t graph. Consider a moving object with initial velocity v0 that undergoes constant acceleration. At time t, the velocity has increased from v0 to v. The distance the object travels between time, t = 0 and time t is the area shaded on the graph.
Total distance traveled is the area under the curve—in this case the sum of the area of the triangle and rectangle
In the graph are two geometrical shapes: a triangle marked “A” and a rectangle marked “B.” The area of triangle is ½ base × height. On the graph this area is ½(vv0)t. We also know that the change in velocity is acceleration × time, so v – v0 = at. Substituting this expression shows that the area of the triangle is ½at2. The area of the rectangle is v0t. Adding these two areas together gives us an equation for the total distance the object moves:
d= v 0 t+ 1 2 a t 2 .
One last step remains to get the equation for position x, because the equation above gives us the total distance d moved, but does not give us position. Distance is a change in position: d = x – x0. Substituting this expression yields equation (2.6), which relates position x at any time t to initial position x0, initial velocity v0, and acceleration a.
(2.6) x= x 0 + v 0 t+ 1 2 a t 2
x  = position (m)
x0  = initial position (m)
v0  = initial speed (m/s)
a  = acceleration (m/s2)
t  = time (s)
Position
in accelerated motion
Equation (2.6) has three terms on the right-hand side, and each term has its own meaning. The first term is the initial position. The second term is the change in position the object would have had if it continued at constant initial speed v0. The third term is the additional change in position due to changes in speed that come from acceleration. Note that if the acceleration is zero, we get back equation (2.2)!
Understanding the different terms in the equation for position as a function of time
A baseball is thrown straight upward and returns to the point from which it was thrown after 5 seconds. Find the baseball's original speed.
  1. 49 m/s
  2. 4.9 m/s
  3. 122.5 m/s
  4. 24.5 m/s
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