The condition for an orbit to be stable is that the force of gravity pulling radially inward should equal the centripetal force required to keep the satellite in its orbit at that radius. If this radial force equilibrium were not met, the satellite would either get closer to, or farther away until the condition was satisfied. We can apply the knowledge from this section to determine the relationship between a satellite’s orbital radius r and its orbital velocity v. The result is the orbit equation for circular orbits.
| r | = | orbital radius (m) | G | = | Grav. const. G = 6.67×10-11 m3/kgs | mE | = | mass of Earth = 6 × 1024 kg | v | = | satellite orbital speed (m/s) |
| Orbit equation for circular orbits |
Almost everyone is familiar with weather satellites. These satellites stay above the same point on Earth so that they can image the same spot 24 hours a day. This “hovering” over the same spot is possible because the satellites are in a special kind of orbit called a
geostationary orbit. A satellite in geostationary orbit completes one orbit in exactly one day, so that its motion follows the motion of the ground underneath it. Many communications and TV broadcast satellites are also in geostationary orbits. This is why a satellite dish antenna can receive a signal 24 hours a day while pointed in a fixed direction. If the TV satellite were not in a geostationary orbit, the dish antenna would have to move around to track the satellite.
To keep up with the Earth’s rotation, a geostationary satellite must travel the entire circumference of its orbit (2πr) in 24 hours (86,400 seconds). To stay in orbit, the satellite’s radius and velocity must also satisfy the orbit equation. The combination of these two conditions determines the radius of geostationary orbit, which is 42,300 kilometers from the center of the Earth. The altitude of the orbit is 35,920 kilometers above the planet’s surface, after subtracting 6,380 kilometers for the radius of Earth itself.
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