Velocity, position, and time relationships

Consider an object that starts at initial position, xi, and moves with constant speed, v. The equation for velocity can be rearranged into a model that relates final position xf to initial position xi, velocity v, and time t. Thinking about the equation as a model is useful because the model can be rearranged in different ways using algebra. Each is useful for solving a different variation of problems involving speed, distance, and time.
Three different ways to express the relationship between speed, position, and time
Velocity can be positive or negative depending on how you define direction. If moving to the right is defined to be positive then a negative velocity, such as −4 m/s, describes moving to the left. You should realize that this is a choice and not a rule of physics. You can choose any direction to be positive, including to the left instead of right, or up, or down. However, you must be consistent with your choice and not change it in the middle of solving a problem!
Positive and negative velocity
Many problems include the term constant speed or constant velocity. This means the value of the velocity v does not change over time. For example, if a problem gives a “constant speed of 10 m/s,” then the velocity stays 10 m/s for all time of interest in the problem. Of course, no real speed stays constant for very long; in many circumstances, however, it is a good approximation. Show Velocity vs. speed
In many physics problems, it is convenient to set the initial time ti to zero. In such cases, the time interval becomes Δt = t and the initial position (at time zero) is written x = x0. Some books and resources use this alternate notation.
Ryan moves to the right with a positive velocity of 5 m/s for 1 second, then to the left with a negative velocity of −5 m/s for 1 second. What is Ryan's displacement after the 2 seconds?
  1. 5 m
  2. 10 m
  3. 0 m
  4. -5 m
Show
Solved Problem 2.1: Time to get from A to B
A train starts in Chicago, passes through St. Louis after traveling 500 km and reaches Baltimore after traveling 1,900 km (total). If the train travels at a constant velocity of 75 kilometers per hour, then how long does it take to get from St. Louis to Baltimore?

Time from St. Louis to Baltimore
xi = 500 km; xf = 1,900 km; v = 75 km/h
t f = t i + x f x i v
Let the time be ti = 0 when the train passes St. Louis. t f =0+ 1,900 km500 km 75 km/hr =18.7 hr
18.7 hours


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