Solved Problem 3.4: Energy losses due to viscous friction | A swimmer applies 100 N of force to swim 25 m across the pool, but the water's viscous friction drags against him with a force of 40 N. (a) How much total work did the swimmer do in crossing the pool? (b) How much work did the swimmer waste in overcoming viscous friction?
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(a) Total work done by the swimmer
(b) Work done overcoming viscous friction
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Force applied by swimmer: Fs=100 N. Resistive force due to viscous friction from water: Ff=40 N.
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Work: W=Fd
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(a) The total work done by the swimmer is calculated using the total force Fs
exerted by the swimmer :
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(b) The work done by the swimmer to overcome viscous friction, Ff, is
calculated using the resistive force due to the water:
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(a) 2,500 J. (b) 1,000 J.
Discussion. The swimmer spent 2,500 J - 1,000 J = 1,500 J of output work in actually moving his body across the pool, which corresponds to a fraction of his input work of 1,500 J/2,500 J = 0.6. We say that his swimming was 60% efficient in converting input work to output work.
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