Friction and losses

Examples of friction:  rock climbing (static friction); baseball player sliding (sliding friction); sky diving (air friction); swimming (viscous friction); and car tire (rolling friction). Friction is all around us in many different forms. A sky diver's fall is slowed down by air resistance when he descends stomach-first. The brake pads on a car slow down the car by rubbing against the rotors in the wheel. A swimmer or a submarine are slowed down in water by fluid friction called viscosity. When you walk, the friction between the sole of your shoe and the ground stops you from sliding—unless you step on a patch of ice! Show Friction and drag
Microscopic view of friction Friction is a “catch-all” term we use to describe forces that are created by motion and that act to resist motion. Since work and energy are closely related, frictional forces represent work done by a moving object on the surroundings. As a result, some energy in the moving object is transformed to other forms of energy in order to overcome friction. A car slows down when the bakes are applied, which is equivalent to saying that the car does work to overcome friction, thereby losing some of its kinetic energy. Show Microscopic view of friction
Work done against friction usually converts kinetic energy into thermal energy (heat). When you rub your two hands together, the friction between them causes them to warm up. The energy used to overcome friction is sometimes called “energy losses”; strictly speaking, however, energy is still conserved. The work done by frictional forces on the surroundings exactly matched the energy gained by the surroundings. The thermal energy gained by the surroundings, however, usually flows out of the system and is “lost” in terms of being available to do other work. Show Brake fade and glazing
Katie pushes on a 10 kg box with 60 N of force, but the box only accelerates by 3 m/s2. How much friction is there?
  1. 2 N
  2. 6 N
  3. 20 N
  4. 30 N
Show
Solved Problem 3.4: Energy losses due to viscous friction
A swimmer applies 100 N of force to swim 25 m across the pool, but the water's viscous friction drags against him with a force of 40 N. (a) How much total work did the swimmer do in crossing the pool? (b) How much work did the swimmer waste in overcoming viscous friction?

(a) Total work done by the swimmer (b) Work done overcoming viscous friction Force diagram for swimmer solved problem
Force applied by swimmer: Fs=100 N. Resistive force due to viscous friction from water: Ff=40 N.
Work: W=Fd
(a) The total work done by the swimmer is calculated using the total force Fs
exerted by the swimmer :
W tot = F s d=(100 N)(25 m)=2,500 J

(b) The work done by the swimmer to overcome viscous friction, Ff, is
calculated using the resistive force due to the water:
W f = F f d=(40 N)(25 m)=1,000 J
(a) 2,500 J. (b) 1,000 J.

Discussion. The swimmer spent 2,500 J - 1,000 J = 1,500 J of output work in actually moving his body across the pool, which corresponds to a fraction of his input work of 1,500 J/2,500 J = 0.6. We say that his swimming was 60% efficient in converting input work to output work.


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