Solving free fall problems with energy conservation

If you drop a ball, what is its speed just before hitting the ground? One way to answer this question would be to use the equations of motion from Chapter 2. Start with the distance equation and solve for time:
h= v 0 t+ 1 2 g t 2 = 1 2 g t 2 t= 2h g
where v0 = 0, because it starts from rest. Then use the speed equation and substitute for time:
v= v 0 +gt=g 2h g v= 2gh
As is often the case in physics, however, the same problem can be solved in another way: using conservation of energy. The ball has gravitational potential energy when it is dropped that is subsequently converted to kinetic energy as it falls.
A ball falls from a height of 8 m. How fast is it traveling when it hits the ground?
  1. 4 m/s
  2. 13 m/s
  3. 78 m/s
  4. 157 m/s
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Solved Problem 3.2: Velocity of a falling baseball
A player drops a ball from rest from his outstretched arm. How fast is the ball moving when it has fallen a distance h?

The speed v of the ball just before hitting the ground. (“How fast is it moving?” is another way of asking for speed.) Determining the speed of a baseball using conservation of energy
Height h the ball has fallen.
Gravitational potential energy: Ep=mgh
Kinetic energy: Ek=½mv2
Conservation of energy: Estart=Eend
To answer the question, let the ball be the system. The force
of gravity is the only influence. The ball can have both
potential energy and kinetic energy but the total energy must
remain constant, Estart=Eend. For simplicity, let the total
energy of the ball be zero before it is dropped, Estart=0. If
the ball falls a height h it changes its potential energy by an
amount −mgh. The total energy of the system, however,
must be zero. Therefore the ball must gain exactly the same
amount of kinetic energy to compensate!
E end = E p + E k =0 = mgh+ 1 2 m v 2 =0 1 2 m v 2 =mgh

With a little algebra we can solve this equation for the speed
of the ball. First, we multiply both sides of the equation
by (2/m) and cancel terms:
2 m ( 1 2 m v 2 )= 2 m (mgh) 2 m ( 1 2 m v 2 )= 2 m ( m gh) v 2 =2gh
Then we take the square root of both sides and arrive at the answer for the speed of the ball v:
v 2 = 2gh v= 2gh
The speed of the baseball is v= 2gh after it has fallen by a height h.

Discussion. Note that the answer does not depend on the mass of the baseball! We have used energy conservation to show that objects will all fall at the same rate, independent of their mass.

Extension. It is easy to use this equation to calculate the ball's speed for various heights. If the ball falls 1 meter its speed will be 4.4 m/s. If it falls 2 meters its speed will be 6.3 m/s. After dropping 3 meters the speed is 7.7 m/s. In short, knowing only the height h that it has dropped, we can predict the speed of the ball at any point along its fall.

Baseball speeds for various dropped heights
Height h [m] 1 2 3 4 6 8 10
Speed v [m/s]4.436.237.678.8510.812.514.0


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