Solved Problem 3.2: Velocity of a falling baseball |
A player drops a ball from rest from his outstretched arm. How fast is the ball moving when it has fallen a distance h?
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The speed v of the ball just before hitting the ground. (“How fast is it moving?” is another way of asking for speed.)
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Height h the ball has fallen.
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Gravitational potential energy: Ep=mgh
Kinetic energy: Ek=½mv2
Conservation of energy: Estart=Eend
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To answer the question, let the ball be the system. The force
of gravity is the only influence. The ball can have both
potential energy and kinetic energy but the total energy must
remain constant, Estart=Eend. For simplicity, let the total
energy of the ball be zero before it is dropped, Estart=0. If
the ball falls a height h it changes its potential energy by an
amount −mgh. The total energy of the system, however,
must be zero. Therefore the ball must gain exactly the same
amount of kinetic energy to compensate!
| With a little algebra we can solve this equation for the speed
of the ball. First, we multiply both sides of the equation
by (2/m) and cancel terms:
| Then we take the square root of both sides and arrive at the answer for the speed of the ball v:
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The speed of the baseball is v= after it has fallen by a height h.
Discussion. Note that the answer does not depend on the mass of the baseball! We have used energy conservation to show that objects will all fall at the same rate, independent of their mass.
Extension. It is easy to use this equation to calculate the ball's speed for various heights. If the ball falls 1 meter its speed will be 4.4 m/s. If it falls 2 meters its speed will be 6.3 m/s. After dropping 3 meters the speed is 7.7 m/s. In short, knowing only the height h that it has dropped, we can predict the speed of the ball at any point along its fall.
Baseball speeds for various dropped heights
Height h [m] | 1 | 2 | 3 | 4 | 6 | 8 | 10 |
Speed v [m/s] | 4.43 | 6.23 | 7.67 | 8.85 | 10.8 | 12.5 | 14.0 |
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