Inelastic collisions

Imagine a collision between two objects with masses m1 and m2. The two objects have initial velocities vi1 and vi2 and final velocities vf1 and vf2. Momentum conservation for these two colliding objects can be written as:
m 1 v i1 + m 2 v i2 = m 1 v f1 + m 2 v f2
m1  = Mass, object 1 (kg)
vi,1  = Initial speed, object 1 (m/s)
vf,1  = Final speed, object 1 (m/s)
m2  = Mass of object 1 (kg)
vi,2  = Initial speed, object 2 (m/s)
vf,2  = Final speed, object 2 (m/s)
Conservation
of momentum
(two objects)
There are two types of collisions in physics: elastic and inelastic. In an inelastic collision, some of the initial kinetic energy of the objects is transformed into heat and/or deforming the shape of the objects. Auto collisions are nearly always inelastic, because of the damage caused to the cars. In the special case of a perfectly inelastic collision, the two objects stick together after impact. Show Symmetry and collisions
Perfectly inelastic collision between two balls
A perfectly inelastic collision is depicted in the illustration above. These collision problems are solved in the same way as any other collision problem, using the conservation of momentum. In the perfectly inelastic collision case, however, the final velocities of the two objects are set to be equal—because they stick together!
Two cars collide head-on, partially crumpling the front end of each. The cars bounce off each other from the collision, ending 1.3 m apart. What kind of collision is this?
  1. Elastic
  2. Inelastic
  3. Perfectly inelastic
  4. Not enough information
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Two 1 kg balls, traveling at +1 m/s and −1 m/s, collide with each other and stick together after impact. What is their speed after the collision?
  1. −1 m/s
  2. 0 m/s
  3. +1 m/s
  4. +2 m/s
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Solved Problem 3.6: Final speed in a perfectly inelastic collision
A 100 kg hockey player, moving at 2 m/s collides, with a 75 kg hockey player, moving at 1 m/s. Both players were moving towards each other. After impact, they become entangled and slide together. What is their speed after impact?

Final speed after collision vf
Mass of first player m1 = 100 kg; Mass of second player m1 = 75 kg;
Initial speed of first player vi,1 = +2 m/s; (choose his direction as the positive direction)
Initial speed of first player vi,1 = -1 m/s (negative because he is moving towards the first player).
Conservation of momentum:
m 1 v i1 + m 2 v i2 = m 1 v f1 + m 2 v f2
Since they move together after the (inelastic) collision, the final speeds are the same vf,1 = vf,2 = vf:
m 1 v i,1 + m 2 v i,2 = m 1 v f,1 + m 2 v f,2 = m 1 v f + m 2 v f =( m 1 + m 2 ) v f
Divide both sides by (m1 + m2):
m 1 v i,1 + m 2 v i,2 m 1 + m 2 = ( m 1 + m 2 ) v f m 1 + m 2
Cancel terms to solve for vf and substitute the values:
v f = m 1 v i,1 + m 2 v i,2 m 1 + m 2 = (100 kg)(2 m/s)+(75 kg)(1 m/s) 100 kg+75 kg =+0.71 m/s
vf = +0.71 m/s. (Positive value means in the same direction as the 100 kg player.)


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